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A sample of aluminum, which has a specific heat capacity of , is put into a calorimeter (see sketch at right) that contains of water. The temperature of the water starts off at . When the temperature of the water stops changing it's . The pressure remains constant at .Calculate the initial temperature of the aluminum sample. Be sure your answer is rounded to significant digits.

User Hanism
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Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:


M=58g

Step-by-step explanation:

From the question we are told that:

Heat Capacity
H=0.897

Mass of water
M=200g

Initial Temperature of Aluminium
T_a=85.6

Initial Temperature of Water
T_(w1)=16.0

Final Temperature of Water
T_(w2)=16.0

Generally

Heat loss=Heat Gain

Therefore


M*0.897*(85.6-20.1) =200*4.184*(20.1-16)


M=58g

User QuentinC
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