Answer:
Casey's monthly charge for making 1,100 minutes of calls is $70.
Explanation:
We can write a piecewise function to model the situation.
Since Casey's phone service only charges a monthly fee of $30 for the first 1000 minutes, we can write that for calling t minutes:
![\displaystyle C(t) = 30\text{ if } t\leq 1000](https://img.qammunity.org/2022/formulas/mathematics/college/3im9uf56lk1q1t3fush8h3zr32g553fege.png)
In other words, the total cost is only $30 is the total minutes of call is less than 1000 minutes.
However, if the total minutes of calls is greater than 1000, then its $0.40 per minute on top of the 30. Thus:
![\displaystyle C(t) = 30 + 0.4(t-1000)\text{ if } t>1000](https://img.qammunity.org/2022/formulas/mathematics/college/nrci5nefipx605dr0818wob4ngv00etd3g.png)
All together, our piecewise function will be:
![\displaystyle C(t) = \begin{cases} 30 & t\leq 1000 \\ 30 + 0.4(t-1000) & t>1000\end{cases}](https://img.qammunity.org/2022/formulas/mathematics/college/7fd8eecz1sg0um36v6qeuegv36u27eu4yn.png)
We want to determine Caseys monthly charge if he makes 1,100 minutes of calls. So, t = 1100. Since 1100 > 1000, we will use the second equation. This yields:
![C(1100)= 30+0.4((1100)-1000)](https://img.qammunity.org/2022/formulas/mathematics/college/sblgnu9fml7qz8e8c782tu81titolr5sph.png)
Evaluate:
![\displaystyle C(1100) = 30+0.4(100) = 30+40=\$70](https://img.qammunity.org/2022/formulas/mathematics/college/rcld3dk0iqopwr28wzrh0oqf9tmoaju4ip.png)
Casey's monthly charge for using 1,100 minutes of call is $70.