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Isobutane (C4H10) is one of the components of natural gas. Which equation

shows the balanced combustion reaction for isobutane?
A. C4H10 + O2 + 4CO2 + H2O + heat
B. C4H10 + O2 + CO2 + H2O + heat
C. C4H10 + O2 + 4C02 + 5H20 + heat
D. C4H10 +6.502 → 4002 + 5H20 + heat
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Isobutane (C4H10) is one of the components of natural gas. Which equation shows the-example-1

1 Answer

4 votes

Answer:

D. C₄H₁₀ + 6.5O₂ → 4CO₂ + 5H₂O + heat

Step-by-step explanation:

The reaction of the combustion of isobutane with oxygen is presented as follows;

C₄H₁₀ + 6.5O₂ → 4CO₂ + 5H₂O + heat

In the above reaction, the number of elements on the reactant side are;

4 carbon, C, atoms, 10 hydrogen, H, atoms, and 13 oxygen, O, atoms

The number of elements on the product side of the above chemical reaction are;

The number of carbon atoms, C = 4

The number of hydrogen atoms, H = 10

The number of oxygen atoms, O = 13

Therefore, the number of atoms on the reactant side of the chemical equation are equal to the number of atoms on the product side, and the combustion reaction for isobutane is balanced.

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