Answer:
8A
Explanation:
We are multiplying the matrix by a scalar
Each term in the first matrix is multiplied by 2
![\left[\begin{array}{ccc}2l&2m&2n\\2p&2q&2r\\2s&2t&2u\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/t8n5jt25ntsd6i76e21v2idy6sa1sspr8x.png)
Factor out 2
![2\left[\begin{array}{ccc}l&m&n\\p&q&r\\s&t&u\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/c2q1bz64i3ltel09e5c7bkoy2wxex22umb.png)
We know that the determinant of a matrix when multiplied by a scalar is found by
det ( a A) =a^n * det (A)
The scalar in this case is 2 and n is the number of rows ( or columns) since the matrix must be square
det (2A) = 2^3 det(A) = 8A