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Please solve this problem

if f(x) = 2x ^ 2 - x + 1 , g(x) = x ^ 2 + 3x - 3 and f(x) = g(x) , then find the possible value of x.​

2 Answers

3 votes

Explanation:

Hey there!

Here;

f(x) = 2x²-x+1

g(X) = x²+3x-3

Since f(X) = g(X);

2x²-x+1 = x²+3x-3

2x²-x²-x-3x+1+3 = 0

x²-4x+4 = 0

(x-2)² = 0

Therefore, the value of X is 2.

Hope it helps!

User Sebastian Rieger
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4 votes

Explanation:

Explanation is in the attachment

Hope it helpful to you

Please solve this problem if f(x) = 2x ^ 2 - x + 1 , g(x) = x ^ 2 + 3x - 3 and f(x-example-1
Please solve this problem if f(x) = 2x ^ 2 - x + 1 , g(x) = x ^ 2 + 3x - 3 and f(x-example-2
User Coraly
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3.3k points