Question

A mass of 5 kg is suspended by a rope of length 2 m from the ceiling. A force of 45 N in the horizontal direction is applied at the midpoint R of the rope, as shown. What is the angle the rope makes with the vertical in equilibrium? (Take g = 10 ms-2). Neglect the mass of the rope.

Answer 1

Step-by-step explanation:

For horizontal equilibrium-

T

3

​

=T

1

​

sinθ

For vertical equilibrium-

T

2

​

=T

1

​

cosθ

Taking ratios-

T

2

​

T

3

​

​

=tanθ

And for equilibrium of body T

2

​

=5kgwt=5×10=50N

⟹tanθ=

6

5

​

or θ=tan

−1

6

5

​