Answer:
(3, 5) and (-4, 12)
Explanation:
To solve this system of equations, we'll use the substitution method.
Plug in the given y = x² - 4 into the other equation
x + x² - 4 = 8
Subtract 8 from both sides
x² + x - 4 = 8
- 8 - 8
x² + x - 12 = 0
Factor out the equation
x² + x - 12 = (x + 4)(x - 3) = 0
For the equation to be 0, x will have to equal -4 and 3
Now plug in the new x's into one of the original equations
We'll use y = x² - 4
y = (-4)² - 4 = 16 - 4 = 12
y = 3² - 4 = 9 - 4 = 5
When x = -4, y = 12, so one of the answers is (-4, 12)
When x = 3, y - 5, so one of the answers is (3, 5)