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Complete the square to rewrite y=x^(2)+8x+3 in vertex form, and then identify the minimum y-value of the function

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Answer:

vertex form: y=a(x−h)^2+k, (h,k) is the vertex

y=x^(2)+8x+3

= (x+4)^2+3-4^2

= (x+4)^2-13

hence, turning point for this function is (-4,-13)

minimum y-value = -13

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