Question

Please help, I'm so confused how to-do this

Answer 1

Explanation:

use the quadratic formula :
`x = ( -b \pm √(b^2 - 4ac))/(2a)`, where ax^2+bx+c=0

`y = ( -(-20) \pm √((-20)^2 - 4(1)(50)))/(2(1))`

`y = ( 20 \pm √(400 - 200))/(2)`

`y = ( 20 \pm √(200))/(2)`

y = 17.07106~ or 2.928932~