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Martin Rauscher · Answer 1 · 2022-05-28T07:06:22+0000

Answer:

See attachment

Explanation:

Given

$\begin{array}{ccccccc}{Marks} & {0-10} & {10-20} & {20-30} & {30-40} & {40-50} & {50-60}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}$

Required

The frequency polygon

We have:

$\begin{array}{ccccccc}{Marks} & {0-10} & {10-20} & {20-30} & {30-40} & {40-50} & {50-60}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}$

First, we calculate the midpoint of each class

$\begin{array}{ccccccc}{Midpoint} & {(0+10)/2} & {(10+20)/2} & {(20+30)/2} & {(30+40)/2} & {(40+50)/2} & {(50+60)/2}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}$

$\begin{array}{ccccccc}{Midpoint} & {5} & {15} & {25} & {35} & {45} & {55}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}$

Lastly, we plot the midpoint against the frequency of students (see attachment)

Draw a frequency polygon for the following data: Marks 0 - 10 10 - 20 20 - 30 30 - 40 40 - 5050 - 60 错误。 No-example-1

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