Answer:
See explanation
Step-by-step explanation:
i) Oxidation half-reaction:
2Ag(s) ----> 2Ag^+(aq) + 2e
Reduction half-reaction:
Ni^2+(aq) + 2e ----> Ni(s)
ii) Ag is the anode while Ni is the cathode
iii) E°cell = E°cathode - E°anode
E°cell = (-0.25) - (0.80)
E°cell = -1.05 V
iv) This is an electrolytic cell since the cell reaction is non spontaneous.