Question

H(n)=n+2

g(n) = 2n + 1

Find h(n) − g(n)

Answer 1

`\\ \rm\rightarrowtail h(n)-g(n)`

`\\ \rm\rightarrowtail n+2-2n-1`

`\\ \rm\rightarrowtail n-2n+2-1`

`\\ \rm\rightarrowtail 1-n`

Answer 2

`h(n) - g(n) = (n+2)-(2n + 1) = n + 2 - 2n -1 = -n + 1`

Hope that helped!