Answer:
i) h(x) = 0 when x = 1, and when x = 5
ii) The graph of h intercepts the x-axis at x = 1 and x = 5
iii) The zeros of h are 1 and 5
Explanation:
Question;
From a similar question on the website, we have;
i) h(x) = 0 when x = _, and when x = _
ii) The graph of h intercepts the x-axis at x = _ and x = _
iii) The zeros of h are _ and _
Explanation;
The given function is h(x) = (2·x - 2)·(x - 5)
When h(x) = 0, we have;
h(x) = (2·x - 2)·(x - 5) = 0
Therefore, we have;
(2·x - 2) = 0/(x - 5) = 0
(2·x - 2) = 0
x = 2/2 = 1
x = 1
Where we proceed with (x - 5) = 0/(2·x - 2) = 0, we get;
(x - 5) = 0/(2·x - 2) = 0
(x - 5) = 0
x = 5
Therefore, when h(x) = 0, x = 1, and x = 5
ii) The graph of h intercepts the x-axis at h(x) = 0, at x = 1, and x = 5
Therefore, the graph of h intercepts the x-axis at (1, 0), and (5, 0)
iii) The zeros of h are the values of x for which h(x) = 0, which are x = 1, and x = 5