Question

The plane of a5cm*8cm rectangular loop of wire is parallel to a 0.19T magnetic field the loop carries a current of 6.2 A. What torque acts on aloop? What is the magnetic moment of the loop?

Answer 1

The torque acting on a rectangular loop parallel to the magnetic field is zero. The magnetic moment of the 5cm x 8cm loop carrying a current of 6.2 A is 0.02496 Am².

Step-by-step explanation:

To calculate the torque (τ) acting on a rectangular loop carrying a current in a magnetic field we use the equation τ = nIABsin(θ), where 'n' is the number of turns, 'I' is the current, 'A' is the area of the loop, 'B' is the strength of the magnetic field, and 'θ' is the angle between the normal to the plane of the loop and the magnetic field. In this case, since the plane of the loop is parallel to the magnetic field, θ is 0 degrees and sin(θ) equals 0. This results in the torque being zero because sin(0) is 0.

The magnetic moment (μ) of the loop is calculated using the equation μ = nIA, where 'n' is the number of turns (which is 1 in this case since it's not specified), 'I' is the current, and 'A' is the area of the loop. For a 5cm x 8cm loop carrying a current of 6.2 A, the magnetic moment is calculated as μ = 1 x 6.2 A x (0.05 m x 0.08 m) = 0.02496 Am².

Answer 2

Torque; τ = 4.712 × 10^(-3) J

Magnetic moment; M = 0.0248 J/T

Step-by-step explanation:

Torque is gotten from the formula;

τ = BIA

Where;

B is magnetic field

I is current

A is area

We are given;

B = 0.19T

I = 6.2A

Rectangle dimensions = 5cm by 8cm = 0.05m by 0.08m

Thus;

Area; A = 0.05m × 0.08m = 0.004 m²

Thus;

τ = 0.19 × 6.2 × 0.004

τ = 4.712 × 10^(-3) J

Formula for the magnetic moment is given by;

M = IA

M = 6.2 × 0.004

M = 0.0248 J/T