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X>0, y>0, 2x+3y=8, smallest value of xy? pls help me
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X>0, y>0, 2x+3y=8, smallest value of xy? pls help me

User AlmightyGOSU
by
5.3k points

1 Answer

1 vote

Answer:

where there is x in the equation we put 0

For y

=2(0)+3y=8

=0+3y=8 Group likely terms

=3y=8-0

=3y=8 Divide both sides by 3

=3y/3=8/3

Therefore y=2.6

For x

=2x+3y=8

=2x+3(0)=8

=2x+0=8 Group likely terms

=2x=8-0

=2x=8 Divide both sides by 2

=2x/2=8/2

Therefore x=4

The smallest numbers for x and y is 4 and 2.6 respectively

User Banny
by
5.2k points
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