Question

A cyclist competes half round of a circular track of a diameter 636m in 1.5 minutes . find the velocity​

Answer 1

Given information:-

• Radius of the circular track is 636 m

• The time elapsed in the journey is 1.5 min or 90 s

• The distance traveled by the cyclist is semi circumference of the circle = πr

`\clubsuit`The displacement of the cyclist will be shortest distance from his initial to final positions which is nothing but diameter of the circle = 2r

We know that,

`\underline{ \boxed{ \sf{Speed = (Distance \: covered )/(Time \: taken)}}}`

`\longrightarrow \sf{(636 * 3.14 m)/(90s)} \\ \\ \longrightarrow \sf22.18 m/s`

• Speed of the cyclist is 22.18 m/s

`\sf{Velocity = (Displacement )/( Time) }`

`\longrightarrow \sf{ (2 * 636m)/(90s) } \\ \\ \longrightarrow \sf{14.13 \: m/s}`

• Velocity of the cyclist is 14.13 m/s

Thank You :)