Question

1. A body moving with uniform acceleration of 10 m/s2 covers a distance of 320 m. if its initial velocity was 60 m/s. Calculate its final velocity.​

Answer 1

• initial velocity=u=60m/s
• Acceleration=10m/s^2=a
• Distance=s=320m
• Final velocity=v

According to third equation of kinematics

`\boxed{\sf v^2-u^2=2as}`

`\\ \sf\longmapsto v^2=u^2+2as`

`\\ \sf\longmapsto v^2=(60)^2+2(10)(320)`

`\\ \sf\longmapsto v^2=3600+3400`

`\\ \sf\longmapsto v^2=10000`

`\\ \sf\longmapsto v=√(10000)`

`\\ \sf\longmapsto v=100m/s`

Answer 2

v² = u² + 2as

v² = 3600 + 6400

v² = 10000

v = 100

Step-by-step explanation:

final velocity is 100 m/s