Question

What is the energy of a photon with a frequency of 3.6 × 1015 Hz? Planck’s constant is 6.63 × 10–34 J•s.

1.8 × 10–49 J
2.4 × 10–19 J
1.8 × 10–18 J
2.4 × 10–18 J

Answer 1

D!!!!!

Step-by-step explanation:

Answer 2

• Frequency =v=3.6×10^15Hz

We know

`\boxed{\sf E=hv}`

`\\ \sf\longmapsto E=6.63* 10^(-34)J* 3.6* 10^(15)s^(-1)`

`\\ \sf\longmapsto E=23.86* 10^(-19)J`

`\\ \sf\longmapsto E=2.38* 10^(-18)J`

`\\ \sf\longmapsto E=2.4* 10^(-18)J`