Given
A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.
To find:
The area of the park excluding the court at the rate of Rs 110 per square meter.
Solution:
Area of a rectangle is:
![Area=length * breadth](https://img.qammunity.org/2022/formulas/mathematics/high-school/fkpwoa67tuipxnwavw0i8snxnb44vigwiv.png)
Area of whole park is:
![A_1=60 * 50](https://img.qammunity.org/2022/formulas/mathematics/high-school/rbj45mtq1a43reyw5neao95uc8ka3wiulw.png)
![A_1=3000](https://img.qammunity.org/2022/formulas/mathematics/high-school/m9y081254l6zlbt8py5h7avey67a9pp27q.png)
Area of volleyball court is:
![A_2=18 * 10](https://img.qammunity.org/2022/formulas/mathematics/high-school/lmtrd64xqbghe42da39lrxoznzpd5pa99i.png)
![A_2=180](https://img.qammunity.org/2022/formulas/mathematics/high-school/5avelmzhdhct0lrpcw44rl1r4ief2qa304.png)
Now, the area of the park excluding the court is:
![A=A_1-A_2](https://img.qammunity.org/2022/formulas/mathematics/high-school/ydp4o7l18accavgujt8meea94g6o0erwal.png)
![A=3000-180](https://img.qammunity.org/2022/formulas/mathematics/high-school/ce1tfh2n2v9r82k5rdlnw651yzwhqhu6nh.png)
![A=2820](https://img.qammunity.org/2022/formulas/mathematics/high-school/iby3emr0pa98y1nzsfcg8um3nah4k0kx5a.png)
Therefore, the area of the park excluding the court is 2820 square meter.