Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?

asked Nov 1, 2022 63.9k views

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2 votes

2 occurred 3times

$\\ \sf\longmapsto S=6* 3=18$

$\\ \sf\longmapsto |S|=18$

Now

$\\ \sf\longmapsto E=No\:of\:times\: 2\:occured$

$\\ \sf\longmapsto |E|=3$

we know

$\boxed)$

$\\ \sf\longmapsto P(E)=(3)/(18)$

$\\ \sf\longmapsto P(E)=(1)/(6)$

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