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Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?​

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2 occurred 3times


\\ \sf\longmapsto S=6* 3=18


\\ \sf\longmapsto |S|=18

Now


\\ \sf\longmapsto E=No\:of\:times\: 2\:occured


\\ \sf\longmapsto |E|=3

we know


\boxed)


\\ \sf\longmapsto P(E)=(3)/(18)


\\ \sf\longmapsto P(E)=(1)/(6)

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