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Find the missing side lengths
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Find the missing side lengths

Find the missing side lengths-example-1
User Martin Brandl
by
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1 Answer

6 votes

Answer:


Sin \: 60=(√(3) )/(u)


u=√(3) /sin\:60


u=√(3) /√(3) /2


u=2

..........................


Cos\: 60=(v)/(2)


v=2\: cos\:60


v=2((1)/(2))


v=1

OAmalOHopeO

User Ehsavoie
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