Find the derivative on the value of x=-4 y=(6x-5)√(8x-3)

asked Nov 6, 2022 91.9k views

2 votes

Find the derivative on the value of x=-4

y=(6x-5)√(8x-3)

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$\\ \sf\longmapsto y=(6x-5)√(8x-3)$

$\\ \sf\longmapsto y=6(-4)-5√(8(-4)-3)$

$\\ \sf\longmapsto y=-24-5√(-32-3)$

$\\ \sf\longmapsto y=-29√(-35)$

$\\ \sf\longmapsto y=-29* 35i$

$\\ \sf\longmapsto y=-1015i$

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