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Find the missing side lengths. Leave your answers as radicals in simplest form.

Find the missing side lengths. Leave your answers as radicals in simplest form.-example-1
Find the missing side lengths. Leave your answers as radicals in simplest form.-example-1
Find the missing side lengths. Leave your answers as radicals in simplest form.-example-2
User Silveris
by
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1 Answer

2 votes

Answer:

Explanation:

For the question 1:

The given is a special right triangle with angle measures of

90-60-30 and side lengths represented by :

a - a
√(3) and 2a

The side length that sees 90 degrees is represented with a

The side length that sees 60 degrees is represented with a
√(3)

The side length that sees 30 degrees is represented with 2a

Here the side length that sees angle measure 60 is given as
√(6)

so a
√(3) =
√(6) to find the value of a we divide
√(6) with
√(3)


(√(6) )/(√(3) ) =
√(2)

so y =
√(2) and x = 2
√(2)

for second question

the square value of hypotenuse is equal to sum of other two side length's square value

10^2 + 6^2 = x^2

100 + 36 = x^2

136 = x^2


√(136) = x

User Deividi Silva
by
5.2k points