Question

What is the phase of y= -3cos (3x-pi) +5

Answer 1

`- (\pi)/(3)`

Explanation:

Given

`y = -3\cos(3x - \pi) + 5`

Required

The phase

We have:

`y = -3\cos(3x - \pi) + 5`

Rewrite as:

`y = -3\cos(3(x - (\pi)/(3))) + 5`

A cosine function is represented as:

`y = A\cos(B(x + C)) + D`

Where:

`C \to` Phase

By comparison:

`C = - (\pi)/(3)`

Hence, the phase is:
`- (\pi)/(3)`