Answer:
0.418 g of CO₂ will be produced
Step-by-step explanation:
Equation of the reaction is given below:
CaCO₃ (s) + 2HCl (aq) ----> CaCl₂(aq) + CO₂ (g) + H₂O (l)
From the equation of reaction , 1 mole of CaCO₃ reacts with 2 molemolesmof HCl to produce 1 mole of CO₂
Number of moles of HCl in 25.7 ml of a 0.738 M solution of HCl is obtained using the formula below:
Number of moles = molarity × volume (Litres)
Number of moles of HCl = 0.738 M × 25.7 mL × 1 L/1000 mL = 0.0190 moles
Since the antacid, Tums will be excess, the limiting reactant is HCl
2 moles of HCl produces 1 mole of CO₂
0.0190 moles of HCl will produce 0.0190 moles ÷ 2 = 0.0095 molesof CO₂
Mass of 0.0095 moles of CO₂ = Numbe of moles × molar mass of CO₂
Molar mass of CO₂ = 44.0 g/mol
Mass of CO₂ produced = 0.00950 moles × 44.0 g/mol = 0.418 g of CO₂
Therefore, 0.418 g of CO₂ will be produced if Tums is added to 25.7 mL of a 0.738 M HCl solution