Answer:
1
Explanation:
As can be seen, for h(t) where t is a multiple of 6, we get -6. Since 150 is a multiple of 6, 153 is 3 more and since the graph visually repeats every 6 units, we can see that h(t) when t is a (multiple of 6) + 3 = 1
Thus h(153)=1