Question

Calculate the elastic energy stored up in a wire originally 5 meter​

long and 10^-3 m in diameter which has been stretched by 3×10^-4 m due to a load of 10 kg.

Answer 1

The elastic energy is 245 J.

Step-by-step explanation:

Length, L = 5 m

Diameter, D = 10^-3 m

Stretch, l = 3 x 10^-4 m

Load, F = 10 x 9.8 = 98 N

Let the elastic energy is U.

`U = (1)/(2)* stress* strain* volume\\\\U = 0.5* (Force)/(area)* (l)/(L)* Area* L\\\\U = 0.5 * F* l\\\\U = 0.5* 98* 5\\\\U = 245 J`