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Resolve 3x-1÷(x+1)^2 into partial fraction


User TheBatman
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1 Answer

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Answer:

3/(x +1) -4/(x +1)^2

Explanation:

The partial fraction expansion will be of the form ...

A/(x+1)^2 +B/(x+1)

We can find the values of A and B by writing the sum of these terms:

= (A +B(x +1))/(x +1)^2

Then we require ...

B = 3

A +B = -1 ⇒ A = -4

So, the desired expansion is ...

3/(x +1) -4/(x +1)^2

User Kviksilver
by
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