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During the 5 minute period described in question 4, the water in the insulated vessel undergoes a temperature increase of 20 C. Assuming all of the electrical energy dissipated by the resistor was transferred to the water as heat, what is the mass of the water

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Answer:

Please find the complete question in the attached file.

Step-by-step explanation:


V=12\ V\\\\I=1.2\ A\\\\T=5* 60=300\ second\\\\

Calculating the electrical energy dissipated:


w=p\cdot t=V\cdot I \cdot t\\\\


=12* 1.2 * 300 \ J\\\\=4320\ J


\Delta T=20^(\circ)\ C\\\\W=m\cdot c\cdot \Delta T\\\\4320=m(4186 * 20)\\\\m=(4320)/(4186 * 20)=51.6 \ grams=0.516 \ kg\\\\

During the 5 minute period described in question 4, the water in the insulated vessel-example-1
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