Question

Assume that the far point of a myopic (nearsighted) eye is 5.04 m in front of the eye. A lens is used to correct the vision, such that it can focus sharply an object at infinity. What is the power of the lens (in diopters; answer sign and magnitude)?

Answer 1

`P=-0.2D`

Step-by-step explanation:

From the question we are told that:

Far-point
`v=-5.04m`

Where

u=-\alpha

Generally the equation for Lens is mathematically given by

`(1)/(f)=(1)/(v)-(1)/(u)`

`P=(1)/(-5.04)-(1)/(\alpha)`

`P=-0.2D`