Question

An AM radio transmitter broadcasts 50.0 kW of power uniformly in all directions. I live 10 km from this station. What is the maximum strength of Electric Field in my house

Answer 1

`E_0=0.173N/C`

Step-by-step explanation:

From the question we are told that:

Power
`P=50kw=>50*10^3w`

Distance
`d=10km=10000m`

Generally the equation for Intensity is mathematically given by

`I=(P)/(4\pi d^2) w/m^2`

`I=(50*10^3)/(4 \pi 10000^2) w/m^2`

`I=3.98*10^(-5)w/m^2`

Generally Intensity is also

`I=(1)/(2)cE_0^2e`

Where

`e=8.854*10^(-12)Nm^2/c^2`

Therefore

`E_0=\sqrt{(2I)/(c *e)}`

`E_0=\sqrt{(2*3.98*10^(-5))/(3*10^8 *8.854*10^(-12))}`

`E_0=0.173N/C`