Answer:
A
Explanation:
Recall that for a quadratic equation of the form:
The number of solutions it has can be determined using its discriminant:
![\Delta = b^2-4ac](https://img.qammunity.org/2022/formulas/mathematics/college/cipjghqau1vz8w08k1xpr70xoflxajb1qb.png)
Where:
- If the discriminant is positive, we have two real solutions.
- If the discriminant is negative, we have no real solutions.
- And if the discriminant is zero, we have exactly one solution.
We have the equation:
![2x^2+5x-k=0](https://img.qammunity.org/2022/formulas/mathematics/college/g2soxcjgizg1crljq66odldd2fbdfdkur1.png)
Thus, a = 2, b = 5, and c = -k.
In order for the equation to have exactly one distinct solution, the discriminant must equal zero. Hence:
![b^2-4ac=0](https://img.qammunity.org/2022/formulas/mathematics/college/uvv1zxlgeai9g54r8ys130ar6uyzk2t69m.png)
Substitute:
![(5)^2-4(2)(-k)=0](https://img.qammunity.org/2022/formulas/mathematics/college/x68wz3734cvqpdi8q4h285x3h6sfg4tvfk.png)
Solve for k. Simplify:
![25+8k=0](https://img.qammunity.org/2022/formulas/mathematics/college/a5jgdr4asnsbr09av0pjr5fi5uqflujv6k.png)
Solve:
![\displaystyle k = -(25)/(8)](https://img.qammunity.org/2022/formulas/mathematics/college/sm8pvihrqzqc8ubpfme2pvrtvtm9ihjaz7.png)
Thus, our answer is indeed A.