Question

A nearsighted person has a near point of 50 cmcm and a far point of 100 cmcm. Part A What power lens is necessary to correct this person's vision to allow her to see distant objects

Answer 1

P = -1 D

Step-by-step explanation:

For this exercise we must use the equation of the constructor

/ f = 1 / p + 1 / q

where f is the focal length, p and q is the distance to the object and the image, respectively

The far view point is at p =∞ and its image must be at q = -100 cm = 1 m, the negative sign is because the image is on the same side as the image

`(1)/(f) = (1)/(infinity) + (1)/(-1)`

f = 1 m

P = 1/f

P = -1 D