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What is the area of triangle ABC? Round to the nearest whole number

What is the area of triangle ABC? Round to the nearest whole number-example-1
User Momeara
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1 Answer

5 votes

9514 1404 393

Answer:

C. 837

Explanation:

The remaining angle is ...

C = 180° -A -B = 180°-62° -67° = 51°

The law of sines tells us that the length AC is ...

AC/sin(B) = AB/sin(C)

AC = AB·sin(B)/sin(C) = 40·sin(67°)/sin(51°)

Using the area formula given, we now have ...

area = 1/2(AB)(AC)sin(A)

= (1/2)(40)(40·sin(67°)sin(62°)/sin(51°) ≈ 836.7

The area of the triangle is about 837 square units.

What is the area of triangle ABC? Round to the nearest whole number-example-1
User Fadedreamz
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6.3k points