Question

A charged particle of mass 0.0040 kg is subjected to a magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius at a speed of what is the magnitude of the charge on the particle

Answer 1

Complete Question

A charged particle of mass 0.0040 kg is subjected to a 40-T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.10 m at a speed of 20m/s, what is the magnitude of the charge on the particle?

Answer:

`q=0.020C`

Step-by-step explanation:

From the question we are told that:

Mass
`m=0.004kg`

Magnetic field
`B=40-T`

Radius
`r=0.10m`

Speed
`v= 20m/s`

Generally the equation for Radius of a circular path is mathematically given by

`r=(p)/(qB)`

Where

`p=mv`

Therefore

`q=(mv)/(rB)`

`q=(0.004kg*20m/s)/(0.1*40)`

`q=0.020C`