Answer:
"125 callers" is the right answer.
Explanation:
Given values:
Arrival calls rate,
= 25 per minute
Talking time,
= 4 minutes
Hold time,
= 1 minute
The flow time will be:
=
![1 \ minute \ + 4 \ minutes](https://img.qammunity.org/2022/formulas/mathematics/college/2qscc5mzojie4cxqaxnuoerprewvcz80sh.png)
=
![5 \ minutes](https://img.qammunity.org/2022/formulas/mathematics/college/svmo25p4lyy5r5bpastt3o3cjohqz5niu7.png)
Flow rate,
=
![Arrival \ calls \ rate](https://img.qammunity.org/2022/formulas/mathematics/college/bvbpkpqpnj2qvvtp6bv2lqa2t7qtwr3mj3.png)
=
![25 \ per \ minute](https://img.qammunity.org/2022/formulas/mathematics/college/hph7bl0hiaxhvjisjo67u5sgcruv1501uf.png)
By using the Little's law,
⇒
![WIP = Flow \ rate* Flow \ time](https://img.qammunity.org/2022/formulas/mathematics/college/ahrm5rqcobkqlfqs3lu0ami717v6cywifw.png)
By substituting the values, we get
![= 25* 5](https://img.qammunity.org/2022/formulas/mathematics/college/kv38zafsiax1exg13shon61r0tklhuzt5h.png)
![=125](https://img.qammunity.org/2022/formulas/mathematics/college/7ibdn3wvzmpyyq681kyhmcbrk2pqruyq6d.png)
Thus the above is the correct approach.