Question

A resistor is submerged in an insulated container of water. A voltage of 12 V is applied to the resistor resulting in a current of 1.2 A. If this voltage and current are maintained for 5 minutes, how much electrical energy is dissipated by the resistor

Answer 1

Step-by-step explanation:

Given:

`\Delta t = 5\:\text{min} = 300\:\text{s}`

`V = 12 V`

`I = 1.2 A`

Recall that power P is given by

`P = VI`

so the amount of energy dissipated
`\Delta E` is given by

`\Delta E = VI\Delta t = (12\:\text{V})(1.2\:\text{A})(300\:\text{s})`

`\:\:\:\:\:\:\:= 4320\:\text{W} = 4.32\:\text{kW}`