Question

A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the probability both beads drawn are green.

A) 16/49
B) 6/7
C) 6/49
D) 9/49

Answer 1

d) 9/49

if you pulled once, the probability would be 3/7. multiply 3/7*3/7 to get 9/49

hope this helps!

Answer 2

9/49

Explanation:

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

Replace the bead

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

P( green , replace, green) = 3/7 * 3/7 = 9/49