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Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. Four percent of the panels from Plant A and 1% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 2%?

User Petrogad
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1 Answer

6 votes

Answer:

The answer is "16,000"

Explanation:

In this question the amounts of panels created by B the x.


\therefore

Calculating the amounts of defective panels from B:


\to (1)/(100) * x = 0.01x

Calculating the amounts of defective panels from A:


\to (4)/(100) * 8000 = 320

Calculating the total defective panels are :


\to 320+ 0.01x

Calculating the total panels manufactured:


\to 8000 + x

when the overall percentage of the defective panels is
2\%


\to ((320 + 0.01x))/((8000 + x)) = 0.02\\\\\to (320 + 0.01x) = 0.02 (8000 + x)\\\\\to 320 + 0.01x = 160 + 0.02x\\\\\to 320 -160 = -0.01x + 0.02x\\\to 160 = 0.01x\\\\\to x=(160)/(0.01)\\\\\to x=16,000\\\\

User Bobby Orndorff
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