Y' = (x+1/\sqrt{x^(2) +1

asked Nov 18, 2022 216k views

4 votes

Y' = (x+1/
$\sqrt{x^(2) +1$

4.4k points

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5 votes

Answer:

Solving for x (rearranging) you get:

(x^3+x+(x^2+1)^1/2)/x^2+1=y

Explanation:

Solve for x by simplifying both sides of the equation and solving for y by isolating y

Moaz Rashad answered Nov 25, 2022

4.7k points

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