Question

The masses of two heavenly bodies are 2×10‘16’ and 4×10 ‘22’ kg respectively and the distance between than is 30000km. find the gravitational force between them ? ans. 2.668× 10-9N​

Answer 1

`F = 5.93×10^(13)\:\text{N}`

Step-by-step explanation:

Given:

`m_1= 2×10^(16)\:\text{kg}`

`m_2= 4×10^(22)\:\text{kg}`

`r = 30000\:\text{km} = 3×10^7\:\text{m}`

Using Newton's universal law of gravitation, we can write

`F = G(m_1m_2)/(r^2)`

`\:\:\:\:=(6.674×10^(-11)\:\text{N-m}^2\text{/kg}^2)\frac{(2×10^(16)\:\text{kg})(4×10^(22)\:\text{kg})}{(3×10^7\:\text{m})^2}`

`\:\:\:\:= 5.93×10^(13)\:\text{N}`