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X+x+y+y+z+z=24

b+x+x+y+z=21

b+b+y+y=28

x+x+x+y+z=23


ASAP PLEASE
what numbers do the variables stand for

all x’s have the same numbers

all b’s have the same numbers

all y’s have the same numbers

all z’s have the same numbers

User Aechlys
by
7.6k points

1 Answer

2 votes

Answer:

b = 7/2

x = 11/2

y = 21/2

z = -4

Explanation:

2x + 2y + 2z = 24

x + y + z = 12

b + 2x + y + z = 21

2b + 2y = 28

b + y = 14

3x + y + z = 23

we can start anywhere by transforming these equations in a way that always one variable is excised by others.

so, e.g.

b = 14 - y

14 - y + 2x + y + z = 21

2x + z = 7

z = 7 - 2x

3x + y + 7 - 2x = 23

x + y = 16

16 + z = 12

z = -4

-4 = 7 - 2x

-11 = -2x

11 = 2x

x = 11/2

11/2 + y = 16

y = 16 - 11/2 = 32/2 - 11/2 = 21/2

b = 14 - 21/2 = 28/2 - 21/2 = 7/2

User Fahrradflucht
by
8.6k points
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