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HELP!!!!

Which of the following is the absolute value of 6 − 3i?

A) 3i√3

B) 3√5

C) 3√5i

D) 3√3

1 Answer

4 votes

Answer:

B

Explanation:

We want to find the value of:


\displaystyle |6-3i|

Recall that given a complex number z in the form:


z=a+bi

The absolute value of z will be given by:


\displaystyle |z| = √(a^2+b^2)

We have the complex number:


6-3i

Thus, a = 6 and b = -3.

Then its absolute value will be:


|6-3i|=√((6)^2+(-3)^2)

Evaluate:


\displaystyle |6-3i|= √(36+9)=√(45)=3√(5)

Hence, our answer is B.

User Kali Charan Rajput
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