Question 1

What will be the molarity of a solution in which 84.5 grams of KNO, are dissolved in 750.0 ml of solution

Question 2

$\\ \large\sf\longmapsto KNO_3$

$\\ \large\sf\longmapsto 39u+14u +3(16u)$

$\\ \large\sf\longmapsto 53u+48u$

$\\ \large\sf\longmapsto 101u$

$\\ \large\sf\longmapsto 101g/mol$

$\boxed{\sf No\:of\:moles=(Given\:mass)/(Molar\:Mass)}$

$\\ \large\sf\longmapsto No\:of\:moles=(84.5)/(101)$

$\\ \large\sf\longmapsto No\:of\:moles=0.8mol$

Now

$\boxed{\sf Molarity=(Moles\:of\:solute)/(Volume\:of\:solution\;in\;L)}$

$\\ \large\sf\longmapsto Molarity=(0.8)/(0.750L)$

$\\ \large\sf\longmapsto Molarity=1.06M$

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