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On a horizontal axis whose unit is the meter, a linear load ranging from 0 to 1 ma a linear load distribution = 2 nC / m.

determine the modulus of the electric field created by the previous loaded bar at the point A of abscissa 2m (we have to find the relation between l, which is the distance between the elementary bar and the point A and x which sweeps the segment [0: 1]

User Chenghwa
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1 Answer

3 votes

Answer:

The correct answer is - 8.99N/C

Step-by-step explanation:


dE=k(dq)/(x^2)\\ dq=\lambda{dx}\\ \lambda=2nC/m\\ dq=2dxnC\\ dE=k(2dx)/(x^2)\\ E=2k\int_1^2(dx)/(x^2)\\ E=2k((-1)/(x))_1^2=k*10^(-9)N/C\\ E=8.99*10^9*10^(-9)N/C\\ E=8.99N/C\\dE=k

User Matt Murphy
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