Question

a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what will be the effort distance ?​

Answer 1

40 cm

Step-by-step explanation:

We are given that

Load=800 N

Effort=200 N

Load distance=10 cm

We have to find the effort distance.

We know that

`load* load\;distance=Effort* effort\;distance`

Using the formula

`800* 10=200* effort\;distance`

Effort distance=
`(800* 10)/(200)`

Effort distance=
`(8000)/(200)`

Effort distance=40 cm

Hence, the effort distance will be 40 cm.