Question

If there is 3.4 m3 of methane gas in a container with a pressure of 18.9 atm and the container expands until the methane has a pressure of 2.2 atm, what is the final volume of the methane? Temperature is constant at 305 K. A. 12.23 m3 B. 141.37 m3 C. 29.21 m3 OD. 2.53 m3​

Answer 1

C. 29.21 m³

Step-by-step explanation:

Given the following data;

• Initial volume, V1 = 3.4 m³
• Initial pressure, P1 = 18.9 atm
• Final pressure, P2 = 2.2 atm

To find the final volume, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

`P_(1)V_(1) = P_(2)V_(2)`

Making V2 the subject of formula, we have;

`V_(2) = \frac {P_(1)V_(1)}{P_(2)}`

Substituting the values into the formula, we have;

`V_(2) = \frac {18.9 * 3.4}{2.2}`

`V_(2) = \frac {64.26}{2.2}`

Final volume, V2 = 29.21 m³