Question

How many moles are there in 13g of KMnO4?

RAM:

K: 39 u

Mn: 55 u

O: 16 u

Answer 1

0.08 Moles would be your answer

Answer 2

0.08 moles

Step-by-step explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

=> Moles in 13g of KMnO4 =
`(Mass)/(Relative-atomic-mass)` =
`(13)/(158)` = 0.082278.. = 0.08 moles