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Find laplace transform of t+t^2 +t^3

User MattoTodd
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1 Answer

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Recall that


L_s\left\{t^n\right\} = (n!)/(s^(n+1))

where
L_s\left\{y(t)\} is the Laplace transform of y(t) into the s-domain.

Then you have


L_s\left\{t+t^2+t^3\right\} = (1!)/(s^(1+1)) + (2!)/(s^(2+1)) + (3!)/(s^(3+1)) = \boxed{\frac1{s^2} + \frac2{s^3} + \frac6{s^4}}

User LiMuBei
by
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