Question

Assuming Faraday constant to be 96500c/mol and relative atomic mass of copper 63,calculate the mass of copper liberated by 2A current in 5min.ans 0.196gm ​

Answer 1

Answer: The mass of copper liberated is 0.196 g.

Step-by-step explanation:

The oxidation half-reaction of copper follows:

`Cu\rightarrow Cu^(2+)+2e^-`

Calculating the theoretical mass deposited by using Faraday's law, which is:

`m=(M* I* t(s))/(n* F)` ......(1)

where,

m = actual mass deposited = ? g

M = molar mass of metal = 63 g/mol

I = average current = 2 A

t = time period in seconds = 5 min = 300 s (Conversion factor: 1 min = 60 sec)

n = number of electrons exchanged = 2

F = Faraday's constant = 96500 C/mol

Putting values in equation 1, we get:

`m=(63 g/mol* 2A* 300s)/(2* 96500 C/mol)\\\\m=0.196g`

Hence, the mass of copper liberated is 0.196 g.